0.07/0.12	% Problem    : theBenchmark.p : TPTP v0.0.0. Released v0.0.0.
0.07/0.13	% Command    : duper %s
0.13/0.34	% Computer : n015.cluster.edu
0.13/0.34	% Model    : x86_64 x86_64
0.13/0.34	% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
0.13/0.34	% Memory   : 8042.1875MB
0.13/0.34	% OS       : Linux 3.10.0-693.el7.x86_64
0.13/0.34	% CPULimit   : 1440
0.13/0.34	% WCLimit    : 180
0.13/0.34	% DateTime   : Mon Jul  3 07:48:24 EDT 2023
0.13/0.34	% CPUTime    : 
3.44/3.62	SZS status Theorem for theBenchmark.p
3.44/3.62	SZS output start Proof for theBenchmark.p
3.44/3.62	Clause #2 (by assumption #[]): Eq (Eq heapIm229596387mpty_b fun T => Eq T e_b) True
3.44/3.62	Clause #5 (by assumption #[]): Eq (Not (heapIm229596387mpty_b e_b)) True
3.44/3.62	Clause #14 (by clausification #[5]): Eq (heapIm229596387mpty_b e_b) False
3.44/3.62	Clause #51 (by clausification #[2]): Eq heapIm229596387mpty_b fun T => Eq T e_b
3.44/3.62	Clause #52 (by argument congruence #[51]): ∀ (a : tree_b), Eq (heapIm229596387mpty_b a) ((fun T => Eq T e_b) a)
3.44/3.62	Clause #57 (by betaEtaReduce #[52]): ∀ (a : tree_b), Eq (heapIm229596387mpty_b a) (Eq a e_b)
3.44/3.62	Clause #58 (by clausify Prop equality #[57]): ∀ (a : tree_b), Or (Eq (heapIm229596387mpty_b a) True) (Eq (Eq a e_b) False)
3.44/3.62	Clause #65 (by clausification #[58]): ∀ (a : tree_b), Or (Eq (heapIm229596387mpty_b a) True) (Ne a e_b)
3.44/3.62	Clause #66 (by destructive equality resolution #[65]): Eq (heapIm229596387mpty_b e_b) True
3.44/3.62	Clause #67 (by superposition #[66, 14]): Eq True False
3.44/3.62	Clause #83 (by clausification #[67]): False
3.44/3.62	SZS output end Proof for theBenchmark.p
3.44/3.63	EOF